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4n^2-6n-54=0
a = 4; b = -6; c = -54;
Δ = b2-4ac
Δ = -62-4·4·(-54)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*4}=\frac{-24}{8} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*4}=\frac{36}{8} =4+1/2 $
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